Derivative Practice Problems
📅 Updated: November 28, 2024
⏱️ 30 min practice
🎯 30 Problems
Test your skills with comprehensive derivative practice problems
from basic to advanced. Challenge yourself with over 30 calculus exercises covering
power rule, chain rule, product rule, quotient rule, trigonometric derivatives, and implicit
differentiation. Try solving each problem before revealing the solution!
💡 How to Practice Effectively
Work through problems on paper first, then click "Show Solution" to check your work. This active
practice approach maximizes learning and retention!
🌱 Level 1: Basic Problems
Practice fundamental derivative rules including power rule and basic combinations.
Find: d/dx[x⁵]
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✅ Solution:
Apply power rule: d/dx[x^n] = n·x^(n-1)
f'(x) = 5x⁴
Find: d/dx[7x³ - 4x² + 9x - 2]
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✅ Solution:
Apply power rule to each term
f'(x) = 21x² - 8x + 9
Find: d/dx[√x]
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✅ Solution:
Rewrite as x^(1/2), then apply power rule
f'(x) = 1/(2√x) or (1/2)x^(-1/2)
Find: d/dx[1/x³]
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✅ Solution:
Rewrite as x^(-3), apply power rule
f'(x) = -3/x⁴ or -3x^(-4)
Find: d/dx[sin(x)]
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✅ Solution:
Basic trig derivative
f'(x) = cos(x)
Find: d/dx[e^x + ln(x)]
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✅ Solution:
d/dx[e^x] = e^x, d/dx[ln(x)] = 1/x
f'(x) = e^x + 1/x
Find: d/dx[5x⁴ - 3x² + 7]
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✅ Solution:
Apply power rule, constant becomes 0
f'(x) = 20x³ - 6x
Find: d/dx[cos(x)]
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✅ Solution:
Trig derivative with negative sign
f'(x) = -sin(x)
Find: d/dx[x^(2/3)]
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✅ Solution:
Power rule with fractional exponent
f'(x) = (2/3)x^(-1/3)
Find: d/dx[tan(x)]
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✅ Solution:
Trig derivative
f'(x) = sec²(x)
⚡ Level 2: Intermediate Problems
Challenge yourself with product rule, chain rule, and quotient rule practice . Review
Chain Rule and
Product Rule
if needed!
Find: d/dx[(x² + 1)(x³ - 2)]
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✅ Solution:
Product rule: (uv)' = u'v + uv'
f'(x) = 2x(x³ - 2) + (x² + 1)(3x²) = 5x⁴ + 3x² - 4x
Find: d/dx[(2x + 1)⁴]
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✅ Solution:
Chain rule: outer derivative × inner derivative
f'(x) = 4(2x + 1)³ · 2 = 8(2x + 1)³
Find: d/dx[x²·sin(x)]
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✅ Solution:
Product rule with trig
f'(x) = 2x·sin(x) + x²·cos(x)
Find: d/dx[sin(3x²)]
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✅ Solution:
Chain rule: cos(3x²) × 6x
f'(x) = 6x·cos(3x²)
Find: d/dx[(x³ + 1)/(x - 2)]
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✅ Solution:
Quotient rule: (u'v - uv')/v²
f'(x) = (3x²(x - 2) - (x³ + 1))/(x - 2)² = (2x³ - 6x² - 1)/(x - 2)²
Find: d/dx[e^(2x)]
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✅ Solution:
Chain rule with exponential
f'(x) = 2e^(2x)
Find: d/dx[ln(x² + 1)]
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✅ Solution:
Chain rule: (1/(x² + 1)) × 2x
f'(x) = 2x/(x² + 1)
Find: d/dx[x·e^x]
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✅ Solution:
Product rule: u' = 1, v' = e^x
f'(x) = e^x + x·e^x = e^x(1 + x)
Find: d/dx[√(x² + 4)]
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✅ Solution:
Chain rule: (1/2)(x² + 4)^(-1/2) × 2x
f'(x) = x/√(x² + 4)
Find: d/dx[cos(x²)]
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✅ Solution:
Chain rule: -sin(x²) × 2x
f'(x) = -2x·sin(x²)
🚀 Level 3: Advanced Problems
Master advanced derivative techniques including nested chains, multiple rules, and
implicit differentiation. Check Implicit Differentiation Guide !
Find: d/dx[sin(cos(x²))]
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✅ Solution:
Triple chain rule
f'(x) = -2x·sin(x²)·cos(cos(x²))
Find dy/dx: x² + y² = 25
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✅ Solution:
Implicit differentiation
dy/dx = -x/y
Find: d/dx[e^(x²)·sin(x)]
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✅ Solution:
Product rule + chain rule
f'(x) = 2x·e^(x²)·sin(x) + e^(x²)·cos(x)
Find: d/dx[(x² + 1)^5·(x - 3)³]
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✅ Solution:
Product rule with chain rule on both terms
f'(x) = 10x(x² + 1)⁴(x - 3)³ + 3(x² + 1)⁵(x - 3)²
Find dy/dx: xy + y² = 10
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✅ Solution:
Implicit differentiation with product rule
dy/dx = -y/(x + 2y)
Find: d/dx[ln(sin(x²))]
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✅ Solution:
Chain rule three times
f'(x) = 2x·cot(x²)
Find: d/dx[sin(x)/x²]
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✅ Solution:
Quotient rule
f'(x) = (x·cos(x) - 2sin(x))/x³
Find: d/dx[e^(sin(x))]
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✅ Solution:
Chain rule with exponential
f'(x) = cos(x)·e^(sin(x))
Find dy/dx: x³ + y³ = 3xy
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✅ Solution:
Implicit differentiation (Folium of Descartes)
dy/dx = (y - x²)/(y² - x)
Find: d/dx[tan(e^(x²))]
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✅ Solution:
Triple chain rule
f'(x) = 2x·e^(x²)·sec²(e^(x²))
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